About this EAMCET Engineering Physics practice test

EAMCET Engineering Physics carries 40 of 160 marks and draws from the same NCERT-aligned Intermediate syllabus most students already have on their shelf — Kinematics, Laws of Motion, Thermodynamics, Electrostatics, Current Electricity, Magnetism, Optics and Modern Physics. What separates a good score here isn't conceptual depth; it's how fast and cleanly you can go from question to formula to number, since the exam gives you barely a minute per question. Each answer below shows the exact formula and substitution used, so you can check your method, not just your final number. Once these feel automatic, regenerate a fresh set from last year's paper to test your pace under real conditions.

EAMCET Engineering Physics Practice Test sample questions

These starter questions help you launch a physics mock test quickly. Swap them with your own worksheet, notebook, or textbook questions any time.

1. 1. The length and breadth of a rectangular sheet are measured as (10.0 ± 0.1) cm and (5.0 ± 0.1) cm respectively. What is the percentage error in the calculated area of the sheet?

2. 2. A pressure of 1.013 × 10^5 Pa is to be expressed in CGS units. What is this pressure in dyne/cm²?

3. 3. A car starting from rest accelerates uniformly at 2 m/s² for 10 s. What distance does it cover in this time?

4. 4. A ball is projected with a speed of 20 m/s at an angle of 30° with the horizontal. Find its time of flight. (Take g = 10 m/s²)

5. 5. A force of 20 N acts on a body of mass 4 kg initially at rest. Find the velocity of the body after 5 s.

6. 6. A block of mass 5 kg rests on a horizontal surface where the coefficient of friction is 0.4. Find the minimum horizontal force needed to just move the block. (Take g = 10 m/s²)

7. 7. A body of mass 2 kg moving at 3 m/s is acted upon by a force that increases its speed to 5 m/s. Find the work done by the force.

8. 8. A pump lifts 200 kg of water through a height of 6 m in 4 s. Find the power delivered by the pump. (Take g = 10 m/s²)

9. 9. A disc has a moment of inertia of 2 kg m² and rotates with an angular speed of 10 rad/s. Find its rotational kinetic energy.

10. 10. Calculate the orbital speed of a satellite revolving very close to the Earth's surface. (Take g = 9.8 m/s², R = 6.4 × 10^6 m)

11. 11. A wire of length 2 m and cross-sectional area 1 × 10⁻⁶ m² is stretched by a force of 100 N, producing an extension of 1 mm. Find the Young's modulus of the wire material.

12. 12. A liquid drop of radius 2 mm has a surface tension of 0.07 N/m. Find the excess pressure inside the drop.

13. 13. An ideal gas absorbs 500 J of heat and does 200 J of work on its surroundings. Find the change in its internal energy.

14. 14. Find the rms speed of oxygen molecules (molar mass 32 g/mol) at 300 K. (Take R = 8.31 J/mol K)

15. 15. A particle executes SHM with amplitude 5 cm and time period 2 s. Find its maximum velocity.

16. 16. A string of length 1 m, fixed at both ends, vibrates in its fundamental mode at a frequency of 100 Hz. Find the speed of transverse waves on the string.

17. 17. Two point charges of +2 μC and +8 μC are separated by 0.3 m in air. Find the electrostatic force between them. (Take k = 9 × 10^9 N m²/C²)

18. 18. Find the electric field intensity at a distance of 0.5 m from a point charge of 5 μC. (Take k = 9 × 10^9 N m²/C²)

19. 19. Two resistors of 4 Ω and 6 Ω are connected in parallel. Find the equivalent resistance of the combination.

20. 20. A heater coil of resistance 40 Ω is connected to a 200 V supply. Find the power consumed by the heater.

21. 21. A straight conductor of length 0.5 m carries a current of 4 A and is placed perpendicular to a magnetic field of 0.2 T. Find the force acting on the conductor.

22. 22. Find the magnetic field at a perpendicular distance of 2 cm from a long straight wire carrying a current of 5 A. (Take μ0/2π = 2 × 10⁻⁷ T m/A)

23. 23. A coil of 200 turns and area 0.05 m² is held perpendicular to a magnetic field that changes uniformly from 0.2 T to 0.8 T in 0.3 s. Find the emf induced in the coil.

24. 24. An AC circuit has an rms voltage of 220 V and an rms current of 2 A, with the current lagging the voltage by 60°. Find the average power consumed.

25. 25. A convex lens of focal length 20 cm forms an image of an object placed 30 cm from the lens. Find the distance of the image from the lens.

26. 26. In a Young's double slit experiment, the slit separation is 0.5 mm and the screen is placed 1 m away. If the fringe width observed is 1.2 mm, find the wavelength of light used.

27. 27. Light of frequency 8 × 10^14 Hz falls on a metal surface whose work function is 2.0 eV. Find the maximum kinetic energy of the emitted photoelectrons. (Take h = 6.63 × 10⁻³⁴ Js, 1 eV = 1.6 × 10⁻¹⁹ J)

28. 28. A radioactive sample has a half-life of 20 days. What fraction of the original sample remains after 60 days?

29. 29. A p-n junction diode has a barrier potential of 0.7 V. If a forward bias of 0.5 V is applied across it, find the resulting net potential barrier.

30. 30. A carrier wave is amplitude modulated by a signal such that the maximum amplitude of the modulated wave is 15 V and the minimum amplitude is 5 V. Find the modulation index.

Answer key & quick explanations

Short answers for the sample questions above. Use this to self-check before generating a fresh AI-built mock test.

1. 1. The length and breadth of a rectangular sheet are measured as (10.0 ± 0.1) cm and (5.0 ± 0.1) cm respectively. What is the percentage error in the calculated area of the sheet?

   3%

   Since area is the product of length and breadth, the percentage errors in the two measured quantities simply add up. Here the percentage error in length is (0.1/10.0)×100 = 1% and in breadth is (0.1/5.0)×100 = 2%, giving a total of 3%.

2. 2. A pressure of 1.013 × 10^5 Pa is to be expressed in CGS units. What is this pressure in dyne/cm²?

   1.013 × 10^6 dyne/cm²

   One pascal equals one newton per square metre, and converting newtons to dynes (×10^5) and square metres to square centimetres (×10^4) shows that 1 Pa = 10 dyne/cm². Multiplying 1.013 × 10^5 Pa by this factor gives 1.013 × 10^6 dyne/cm².

3. 3. A car starting from rest accelerates uniformly at 2 m/s² for 10 s. What distance does it cover in this time?

   100 m

   Using s = ut + ½at² with u = 0, a = 2 m/s² and t = 10 s, the distance works out to s = ½ × 2 × 10² = 100 m. No initial velocity term contributes since the car starts from rest.

4. 4. A ball is projected with a speed of 20 m/s at an angle of 30° with the horizontal. Find its time of flight. (Take g = 10 m/s²)

   2 s

   Time of flight for a projectile is given by T = 2u sinθ/g. Substituting u = 20 m/s, θ = 30° (sin30° = 0.5) and g = 10 m/s² gives T = 2 × 20 × 0.5/10 = 2 s.

5. 5. A force of 20 N acts on a body of mass 4 kg initially at rest. Find the velocity of the body after 5 s.

   25 m/s

   Newton's second law gives the acceleration as a = F/m = 20/4 = 5 m/s². Applying v = u + at with u = 0 and t = 5 s gives v = 5 × 5 = 25 m/s.

6. 6. A block of mass 5 kg rests on a horizontal surface where the coefficient of friction is 0.4. Find the minimum horizontal force needed to just move the block. (Take g = 10 m/s²)

   20 N

   To just move the block, the applied force must equal the maximum friction force, f = μmg. Substituting μ = 0.4, m = 5 kg and g = 10 m/s² gives f = 0.4 × 5 × 10 = 20 N.

7. 7. A body of mass 2 kg moving at 3 m/s is acted upon by a force that increases its speed to 5 m/s. Find the work done by the force.

   16 J

   By the work-energy theorem, the work done equals the change in kinetic energy. Here ΔKE = ½m(v² − u²) = ½ × 2 × (5² − 3²) = 1 × 16 = 16 J.

8. 8. A pump lifts 200 kg of water through a height of 6 m in 4 s. Find the power delivered by the pump. (Take g = 10 m/s²)

   3000 W (3 kW)

   The work done in lifting the water is W = mgh = 200 × 10 × 6 = 12000 J. Power is work done per unit time, so P = 12000/4 = 3000 W.

9. 9. A disc has a moment of inertia of 2 kg m² and rotates with an angular speed of 10 rad/s. Find its rotational kinetic energy.

   100 J

   Rotational kinetic energy is given by KE = ½Iω². Plugging in I = 2 kg m² and ω = 10 rad/s gives KE = ½ × 2 × 10² = 100 J.

10. 10. Calculate the orbital speed of a satellite revolving very close to the Earth's surface. (Take g = 9.8 m/s², R = 6.4 × 10^6 m)

    ≈ 7.92 km/s (7920 m/s)

    For a satellite orbiting just above the Earth's surface, gravity supplies the centripetal force, giving orbital speed v = √(gR). Substituting g = 9.8 m/s² and R = 6.4 × 10^6 m gives v = √(6.272 × 10^7) ≈ 7920 m/s, or about 7.92 km/s.

11. 11. A wire of length 2 m and cross-sectional area 1 × 10⁻⁶ m² is stretched by a force of 100 N, producing an extension of 1 mm. Find the Young's modulus of the wire material.

    2 × 10^11 Pa (N/m²)

    Young's modulus is defined as Y = (F/A)/(ΔL/L) = FL/(AΔL). Substituting F = 100 N, L = 2 m, A = 1 × 10⁻⁶ m² and ΔL = 1 × 10⁻³ m gives Y = 200/(1 × 10⁻⁹) = 2 × 10^11 Pa.

12. 12. A liquid drop of radius 2 mm has a surface tension of 0.07 N/m. Find the excess pressure inside the drop.

    70 Pa

    For a liquid drop with a single free surface, the excess pressure inside is ΔP = 2T/r. With T = 0.07 N/m and r = 2 × 10⁻³ m, this gives ΔP = 0.14/0.002 = 70 Pa.

13. 13. An ideal gas absorbs 500 J of heat and does 200 J of work on its surroundings. Find the change in its internal energy.

    300 J (increase)

    The first law of thermodynamics states ΔU = Q − W, where Q is heat absorbed and W is work done by the gas. Here ΔU = 500 − 200 = 300 J, an increase in internal energy.

14. 14. Find the rms speed of oxygen molecules (molar mass 32 g/mol) at 300 K. (Take R = 8.31 J/mol K)

    ≈ 483 m/s

    The rms speed of gas molecules is v_rms = √(3RT/M), where M must be in kg/mol. Using R = 8.31 J/mol K, T = 300 K and M = 0.032 kg/mol gives v_rms = √(7479/0.032) = √233718.75 ≈ 483 m/s.

15. 15. A particle executes SHM with amplitude 5 cm and time period 2 s. Find its maximum velocity.

    ≈ 0.157 m/s (15.7 cm/s)

    In SHM, the maximum speed is v_max = Aω, where ω = 2π/T. With A = 0.05 m and T = 2 s, ω = π rad/s, so v_max = 0.05 × π ≈ 0.157 m/s.

16. 16. A string of length 1 m, fixed at both ends, vibrates in its fundamental mode at a frequency of 100 Hz. Find the speed of transverse waves on the string.

    200 m/s

    For a string fixed at both ends vibrating in its fundamental mode, the frequency is f = v/2L, so v = 2Lf. With L = 1 m and f = 100 Hz, v = 2 × 1 × 100 = 200 m/s.

17. 17. Two point charges of +2 μC and +8 μC are separated by 0.3 m in air. Find the electrostatic force between them. (Take k = 9 × 10^9 N m²/C²)

    1.6 N

    Coulomb's law gives F = kq1q2/r². Substituting q1 = 2 × 10⁻⁶ C, q2 = 8 × 10⁻⁶ C and r = 0.3 m gives F = 9 × 10^9 × 16 × 10⁻¹²/0.09 = 1.6 N.

18. 18. Find the electric field intensity at a distance of 0.5 m from a point charge of 5 μC. (Take k = 9 × 10^9 N m²/C²)

    1.8 × 10^5 N/C

    Electric field due to a point charge is E = kq/r². With q = 5 × 10⁻⁶ C and r = 0.5 m, E = 9 × 10^9 × 5 × 10⁻⁶/0.25 = 1.8 × 10^5 N/C.

19. 19. Two resistors of 4 Ω and 6 Ω are connected in parallel. Find the equivalent resistance of the combination.

    2.4 Ω

    For resistors in parallel, 1/R = 1/R1 + 1/R2. With R1 = 4 Ω and R2 = 6 Ω, R = (4 × 6)/(4 + 6) = 24/10 = 2.4 Ω.

20. 20. A heater coil of resistance 40 Ω is connected to a 200 V supply. Find the power consumed by the heater.

    1000 W (1 kW)

    Power dissipated in a resistor connected to a voltage source is P = V²/R. Substituting V = 200 V and R = 40 Ω gives P = 40000/40 = 1000 W.

21. 21. A straight conductor of length 0.5 m carries a current of 4 A and is placed perpendicular to a magnetic field of 0.2 T. Find the force acting on the conductor.

    0.4 N

    The force on a current-carrying conductor in a perpendicular magnetic field is F = BIL. With B = 0.2 T, I = 4 A and L = 0.5 m, F = 0.2 × 4 × 0.5 = 0.4 N.

22. 22. Find the magnetic field at a perpendicular distance of 2 cm from a long straight wire carrying a current of 5 A. (Take μ0/2π = 2 × 10⁻⁷ T m/A)

    5 × 10⁻⁵ T

    The magnetic field due to a long straight current-carrying wire is B = (μ0/2π)(I/r). Using μ0/2π = 2 × 10⁻⁷ T m/A, I = 5 A and r = 0.02 m, B = 2 × 10⁻⁷ × 5/0.02 = 5 × 10⁻⁵ T.

23. 23. A coil of 200 turns and area 0.05 m² is held perpendicular to a magnetic field that changes uniformly from 0.2 T to 0.8 T in 0.3 s. Find the emf induced in the coil.

    20 V

    Faraday's law gives the induced emf as ε = N(ΔΦ/Δt) = NA(ΔB/Δt). Here N = 200, A = 0.05 m² and ΔB/Δt = 0.6/0.3 = 2 T/s, so ε = 200 × 0.05 × 2 = 20 V.

24. 24. An AC circuit has an rms voltage of 220 V and an rms current of 2 A, with the current lagging the voltage by 60°. Find the average power consumed.

    220 W

    Average power in an AC circuit is P = V_rms I_rms cosφ. With V_rms = 220 V, I_rms = 2 A and φ = 60° (cos60° = 0.5), P = 220 × 2 × 0.5 = 220 W.

25. 25. A convex lens of focal length 20 cm forms an image of an object placed 30 cm from the lens. Find the distance of the image from the lens.

    60 cm

    Applying the lens formula 1/v − 1/u = 1/f with the Cartesian sign convention, u = −30 cm and f = +20 cm. Then 1/v = 1/20 − 1/30 = 1/60, giving v = 60 cm, so the image forms 60 cm on the other side of the lens.

26. 26. In a Young's double slit experiment, the slit separation is 0.5 mm and the screen is placed 1 m away. If the fringe width observed is 1.2 mm, find the wavelength of light used.

    600 nm

    Fringe width in Young's double slit experiment is β = λD/d, so λ = βd/D. Substituting β = 1.2 × 10⁻³ m, d = 0.5 × 10⁻³ m and D = 1 m gives λ = 6 × 10⁻⁷ m = 600 nm.

27. 27. Light of frequency 8 × 10^14 Hz falls on a metal surface whose work function is 2.0 eV. Find the maximum kinetic energy of the emitted photoelectrons. (Take h = 6.63 × 10⁻³⁴ Js, 1 eV = 1.6 × 10⁻¹⁹ J)

    ≈ 1.32 eV

    The energy of each incident photon is E = hf = 6.63 × 10⁻³⁴ × 8 × 10^14 = 5.304 × 10⁻¹⁹ J, which equals 3.315 eV. Using Einstein's photoelectric equation, KE_max = E − φ0 = 3.315 − 2.0 ≈ 1.32 eV.

28. 28. A radioactive sample has a half-life of 20 days. What fraction of the original sample remains after 60 days?

    1/8 (0.125)

    The remaining fraction after n half-lives is (1/2)^n. Since 60 days corresponds to 60/20 = 3 half-lives, the fraction remaining is (1/2)^3 = 1/8.

29. 29. A p-n junction diode has a barrier potential of 0.7 V. If a forward bias of 0.5 V is applied across it, find the resulting net potential barrier.

    0.2 V

    Forward bias opposes the built-in barrier potential of the junction, reducing it directly. So the net barrier becomes 0.7 − 0.5 = 0.2 V.

30. 30. A carrier wave is amplitude modulated by a signal such that the maximum amplitude of the modulated wave is 15 V and the minimum amplitude is 5 V. Find the modulation index.

    0.5

    The modulation index for an AM wave is m = (A_max − A_min)/(A_max + A_min). Substituting A_max = 15 V and A_min = 5 V gives m = 10/20 = 0.5.

Curriculum Mapping & Learning Guide

Use this breakdown to identify which skills each question tests and guide post-test review.

EAMCET Engineering Physics units covered

1. Chapter 1: Units and Measurements
2. Chapter 2: Motion in a Straight Line and a Plane
3. Chapter 3: Laws of Motion and Friction
4. Chapter 4: Work, Energy and Power
5. Chapter 5: Rotational Motion and Gravitation
6. Chapter 6: Mechanical Properties of Matter
7. Chapter 7: Thermodynamics and Kinetic Theory
8. Chapter 8: Oscillations and Waves
9. Chapter 9: Electric Charges and Fields
10. Chapter 10: Current Electricity
11. Chapter 11: Moving Charges and Magnetism
12. Chapter 12: Electromagnetic Induction and Alternating Current
13. Chapter 13: Electromagnetic Waves and Optics
14. Chapter 14: Dual Nature of Matter, Atoms and Nuclei
15. Chapter 15: Semiconductors and Communication

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