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IBPS PO Quantitative Aptitude Practice Test Online

IBPS PO Quantitative Aptitude is where Data Interpretation alone can swing 15-20 of the section's marks, so this page drills table, bar-graph and pie-chart reading until the calculation — not the reading — becomes the bottleneck. The same speed carries straight into Percentage, Interest and Time-Work questions built for a strict 20-minute sectional clock.

IBPS POQuantitative Aptitude
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Reviewed by Siva · Assistant Manager, SBI Machilipatnam · Selected through IBPS PO.Data Interpretation sets, quadratic-comparison pairs, and arithmetic word problems checked against current IBPS PO Prelims difficulty and question style.

Last reviewed: September 2026

Exam strategy & syllabus overview

Quantitative Aptitude in IBPS PO puts more weight on Data Interpretation than almost any other Indian competitive exam — DI sets alone can account for 15–20 of the 35 Prelims marks. The rest is built from Number Series, Simplification and Approximation, Quadratic Equations, and Arithmetic chapters like Percentage, Profit/Loss, Simple/Compound Interest, Time-Work-Pipes, Speed-Distance-Time and Mixtures & Alligation, and because every one of these rewards calculation speed over conceptual difficulty, consistent timed practice is what actually moves your score across IBPS PO, SBI PO and IBPS Clerk.

This page is scoped to the IBPS PO Prelims Quantitative Aptitude paper: 35 questions, 30 marks, 20 minutes, +1 for a correct answer and -0.25 for a wrong one. The same calculation habits extend directly into the tougher, 45-minute Mains Data Analysis & Interpretation module.

⚡ Quick quiz

Test yourself in under a minute: IBPS PO Quantitative Aptitude Practice Test

A fresh set spanning Data Interpretation, Number Series, Quadratic Comparison and Interest — the same speed-under-pressure check, different numbers from the practice set above.

  1. 1. A shop's monthly sales were Rs 45,000 in March and Rs 54,000 in April. What was the percentage increase in sales from March to April?

  2. 2. Find the missing term: 4, 9, 19, 39, 79, ?

  3. 3. I. x^2 - 5x + 6 = 0 II. y^2 - 9y + 20 = 0. What is the relationship between x and y?

  4. 4. A's salary is 25% more than B's salary. By what percentage is B's salary less than A's?

  5. 5. Find the compound interest on Rs 10,000 for 2 years at 10% per annum, compounded annually.

  6. 6. A train 180 metres long crosses a pole in 12 seconds. Find its speed in km/h.

⏱ Cutoff & exam pattern

Target Score: 19-22+ out of 30 in Prelims (within 16-18 minutes)

Given a data table you've never seen before, can you pull the one number a question actually needs in under 15 seconds, without re-reading the whole table for every sub-question?

Prelims pattern

35 Qs / 30 Marks, 20 min (qualifying, -0.25 penalty)

Mains (Data Analysis & Interpretation) pattern

40 Qs / 60 Marks, 45 min (-0.25 penalty)

Data Interpretation, Series & Simplification

10 Qs

Percentage, Quadratic & Profit-Loss Basics

10 Qs

Discounts, Interest, Time-Work & Mixtures

10 Qs

Prelims Sectional Cut-off (General)

7-9 out of 30

Time yourself on this set the way you would in the actual exam — accuracy under a clock is the real skill being tested here.

Data Interpretation, Number Series and Simplification

Questions 1-10 build speed in reading tables, bar graphs, pie charts and line graphs, spotting patterns to find missing terms in number series, and simplifying arithmetic expressions accurately under time pressure.

📋 Quick referenceData Interpretation & Number Series Quick Reference▶
  • DI: pull every sub-question's needed totals from the same table read, don't re-scan for every part.
  • Number series: test constant difference, then ratio/multiplication, then an alternating pattern, in that order.
  • Simplification: BODMAS left to right within each precedence level, not 'easiest term first'.

Reading the Chart Before Touching a Number

  • Skim the whole table, bar graph or pie chart once before solving any part of it; the sub-questions usually reuse the same totals.
  • Number series rules almost always reveal themselves within the first three gaps; test constant-difference, then ratio, then an alternating pattern before assuming anything unusual.
  • For Simplification, apply BODMAS strictly left to right within each precedence level; reordering steps from memory is the most common self-inflicted error.

  1. 1. Data Interpretation (Set 1): The table below shows the sales (in thousand units) of three products - X, Y and Z - by a company over three years.

    ▶Reveal answer
    1,100 thousand units

    Add the 2022 figures for all three products: 380 (X) + 300 (Y) + 420 (Z) = 1,100 thousand units.

  2. 2. Product X: 2021 = 320, 2022 = 380, 2023 = 450

    ▶Reveal answer
    40.625% (approx. 40.63%)

    Increase = 450 - 320 = 130. Percentage increase = (130/320) x 100 = 40.625%.

  3. 3. Product Y: 2021 = 250, 2022 = 300, 2023 = 275

    ▶Reveal answer
    approx. 10.83%

    Total 2022 = 240+300+180+260+220 = 1,200. Total 2023 = 280+270+220+300+260 = 1,330. Increase = 130, so % increase = (130/1200) x 100 = 10.83%.

  4. 4. Product Z: 2021 = 400, 2022 = 420, 2023 = 460

    ▶Reveal answer
    11:15

    School R in 2023 = 220 and School S in 2023 = 300. Dividing both by their HCF (20) gives 220:300 = 11:15.

  5. 5. What is the total combined sales (in thousand units) of all three products in the year 2022?

    ▶Reveal answer
    Rs 6,000

    Food = 20% of 60,000 = Rs 12,000; Transport = 10% of 60,000 = Rs 6,000. Difference = 12,000 - 6,000 = Rs 6,000.

  6. 6. Data Interpretation (Set 1 contd.): Using the same sales table as above, what is the percentage increase in the sales of Product X from 2021 to 2023?

    ▶Reveal answer
    approx. 79.17 mm

    Sum of rainfall = 60+45+90+75+110+95 = 475 mm over 6 months. Average = 475/6 = 79.17 mm.

  7. 7. Data Interpretation (Set 2): A bar graph shows the number of students enrolled in five schools - P, Q, R, S and T - during 2022 and 2023.

    ▶Reveal answer
    129

    Each term is obtained as (previous term x 2) - 1: 5x2-1=9, 9x2-1=17, 17x2-1=33, 33x2-1=65, 65x2-1=129.

  8. 8. School P: 2022 = 240, 2023 = 280

    ▶Reveal answer
    58

    The differences between consecutive terms increase by 3 each time: 4, 7, 10, 13, 16. So the next term = 42 + 16 = 58.

  9. 9. School Q: 2022 = 300, 2023 = 270

    ▶Reveal answer
    15,120

    Each term is obtained by multiplying the previous term by an increasing factor (3,4,5,6,7): 360x6=2160, and 2160x7=15,120.

  10. 10. School R: 2022 = 180, 2023 = 220

    ▶Reveal answer
    17

    (15x18)/9 = 270/9 = 30. 144/12 = 12. So the expression becomes 30 + 12 - 25 = 17.

Simplification, Approximation, Quadratic Equations, Percentage and Profit-Loss Basics

Questions 11-20 open with an approximation shortcut before moving to a simplification problem, solving paired quadratic equations to compare x and y, core percentage applications like pass marks and population change, and foundational profit/discount calculations.

📋 Quick referencePercentage & Quadratic Comparison Quick Reference▶
  • Quadratic comparison: solve both equations completely, then check every x-y pair before declaring x>y, x<y, x=y, or 'cannot be determined'.
  • Percentage change compounds by multiplication, not addition: +20% then -15% = x1.20 x0.85.
  • SP = CP x (1 + profit%/100), or CP x (1 - loss%/100).

Deciding Definite vs. Indeterminate Before Comparing

  • For quadratic comparison questions, solve both equations fully and check every possible x-y pair. One matching pair isn't enough to call a relationship definite.
  • Approximation rewards rounding to a number the answer options can tell apart, not full precision.
  • Convert a percentage change straight into a multiplier (a 20% rise becomes x1.20) instead of separately adding and subtracting each step.
  • Profit-loss basics almost always reduce to SP = CP x (1 + profit%/100); write that relationship down before plugging in numbers.

  1. 1. School S: 2022 = 260, 2023 = 300

    ▶Reveal answer
    approx. 358

    48.97% of 650 is close to 49% of 650 = 318.5 (exact 318.305); adding 39.98 (approx. 40) gives approximately 358.

  2. 2. School T: 2022 = 220, 2023 = 260

    ▶Reveal answer
    81

    7/9 of 162 = 126. 5/8 of 96 = 60. So the expression is 126 - 60 + 15 = 81.

  3. 3. What is the overall percentage increase in the total number of students across all five schools from 2022 to 2023?

    ▶Reveal answer
    x <= y

    Factorising gives x = 5 or 6, and y = 6 or 7. Comparing every possible pair, x is always less than or equal to y, so x <= y.

  4. 4. Data Interpretation (Set 2 contd.): Using the same bar graph data, what is the ratio of the number of students in School R to School S in the year 2023?

    ▶Reveal answer
    Relationship cannot be determined

    Solving gives x = 2 or 2.5, and y = 1.5 or 4. Some pairs give x>y (2 vs 1.5) and others give x<y (2 vs 4), so no fixed relation exists.

  5. 5. Data Interpretation: A family's monthly income of Rs 60,000 is distributed as follows - Rent 25%, Food 20%, Education 15%, Transport 10%, Savings 20%, Others 10%. How much more does the family spend on Food than on Transport every month?

    ▶Reveal answer
    x >= y

    Factorising gives x = 3 or 4, and y = 2 or 3. Checking all pairs, x is always greater than or equal to y, so x >= y.

  6. 6. Data Interpretation: A line graph shows the rainfall (in mm) recorded in a city over six months - January = 60, February = 45, March = 90, April = 75, May = 110, June = 95. What is the average monthly rainfall (in mm) recorded over these six months?

    ▶Reveal answer
    500

    Passing marks = 189 + 36 = 225, which is 45% of the maximum marks. Maximum marks = 225 / 0.45 = 500.

  7. 7. Find the missing term in the series: 5, 9, 17, 33, 65, ?

    ▶Reveal answer
    20,000

    Net multiplier = 1.20 x 0.85 = 1.02. Since 1.02 x original population = 20,400, original population = 20,400 / 1.02 = 20,000.

  8. 8. Find the missing term in the series: 8, 12, 19, 29, 42, ?

    ▶Reveal answer
    approx. 28.57% (200/7 %)

    If B = 100, A = 140. B is less than A by (40/140) x 100 = 28.57%.

  9. 9. Find the missing term in the series: 6, 18, 72, 360, 2160, ?

    ▶Reveal answer
    19%

    Taking CP = 100, MP = 140. SP after 15% discount = 140 x 0.85 = 119. Profit = 19, so profit% = 19%.

  10. 10. Simplify: (15 x 18) / 9 + 144 / 12 - 25 = ?

    ▶Reveal answer
    4% loss

    CP1 = 1920/1.20 = 1600 and CP2 = 1920/0.80 = 2400, so total CP = 4000 while total SP = 3840. Loss = 160, giving loss% = (160/4000) x 100 = 4%.

Discounts, Interest, Time-Work-Pipes, Speed-Trains and Mixtures

Questions 21-30 focus on successive discounts, simple and compound interest including the CI-SI difference shortcut, time and work with pipes and cisterns, speed-distance-time and train-crossing problems, and alligation-based mixture questions.

📋 Quick referenceDiscounts, Interest & Time-Work Quick Reference▶
  • Successive discounts: multiply the surviving fractions (20% then 10% off = x0.80 x0.90), never add the percentages.
  • CI - SI over 2 years = P x (rate/100)^2.
  • Combined work rate = 1/(time A) + 1/(time B); an emptying pipe's rate is subtracted, not added.

One Formula, Applied Directly, Beats a Long Derivation

  • Successive discounts multiply against the marked price in sequence; never add the discount percentages together.
  • The CI-SI difference for 2 years reduces to one formula, P x (rate/100)^2; use it directly instead of computing CI and SI separately.
  • For pipes and cisterns, an emptying pipe's rate subtracts from the combined rate; write every rate with its correct sign before adding.
  • Alligation ratio = (dearer price - mean price) : (mean price - cheaper price); place the mean price between both given prices first.

  1. 1. Find the approximate value of: 48.97% of 650 + 39.98

    ▶Reveal answer
    Effective discount 28%; SP = Rs 1,800

    After 20% off, price = 2500 x 0.80 = 2000; after a further 10% off, price = 2000 x 0.90 = 1800. Effective discount = (2500-1800)/2500 x 100 = 28%.

  2. 2. Simplify: (7/9 of 162) - (5/8 of 96) + 15 = ?

    ▶Reveal answer
    Rs 2,400

    Time = 3 years 4 months = 10/3 years. SI = (8000 x 9 x 10/3)/100 = 720000/300 = Rs 2,400.

  3. 3. I. x^2 - 11x + 30 = 0 II. y^2 - 13y + 42 = 0. Solve both equations and determine the relationship between x and y.

    ▶Reveal answer
    Rs 3,150

    CI = P[(1+r/100)^n - 1] = 15000[(1.1)^2 - 1] = 15000 x 0.21 = Rs 3,150.

  4. 4. I. 2x^2 - 9x + 10 = 0 II. 2y^2 - 11y + 12 = 0. Solve both equations and determine the relationship between x and y.

    ▶Reveal answer
    Rs 80,000

    For 2 years, CI - SI = P x (r/100)^2. So P x (0.08)^2 = 512, giving P = 512/0.0064 = Rs 80,000.

  5. 5. I. x^2 - 7x + 12 = 0 II. y^2 - 5y + 6 = 0. Solve both equations and determine the relationship between x and y.

    ▶Reveal answer
    5 days

    A's rate = 1/15, B's rate = 1/10; combined = 1/6 per day. In 3 days, 3/6 = 1/2 of the work is done, leaving 1/2. B alone at 1/10 per day needs (1/2)/(1/10) = 5 days.

  6. 6. In an exam, a student needs 45% of the total marks to pass. He scored 189 marks and failed by 36 marks. Find the maximum marks of the exam.

    ▶Reveal answer
    36 hours

    Rates: A = 1/12, B = 1/18, C = -1/9. Combined = 3/36 + 2/36 - 4/36 = 1/36 per hour, so the tank fills in 36 hours.

  7. 7. The population of a town increased by 20% in the first year and then decreased by 15% in the second year. If the population after two years is 20,400, find the original population.

    ▶Reveal answer
    50 km/h

    Time for first leg = 60/40 = 1.5 h; time for second leg = 90/60 = 1.5 h. Total distance 150 km in total time 3 h gives average speed = 150/3 = 50 km/h.

  8. 8. A's income is 40% more than B's income. By what percentage is B's income less than A's income?

    ▶Reveal answer
    approx. 34.29 seconds (240/7 s)

    Speed = 63 km/h = 17.5 m/s. Distance to cover = train length + platform length = 240+360 = 600 m. Time = 600/17.5 = 240/7 = approx. 34.29 seconds.

  9. 9. A shopkeeper marks an article 40% above its cost price and then allows a discount of 15% on the marked price. Find his profit percentage.

    ▶Reveal answer
    3:2

    Required cost price of the mixture = SP/(1+profit%) = 264/1.2 = Rs 220. By alligation, ratio = (280-220):(220-180) = 60:40 = 3:2 (cheaper:dearer).

  10. 10. A trader sold two watches for Rs 1,920 each. On one he gained 20% and on the other he lost 20%. Find his overall gain or loss percentage on the whole transaction.

    ▶Reveal answer
    10 litres

    Initially milk = 30 L and water = 10 L (3:1 of 40 L). Milk stays fixed; for milk:water = 3:2, water needed = (2/3) x 30 = 20 L, so 20-10 = 10 litres must be added.

Additional practice

  1. 1. A shopkeeper allows successive discounts of 20% and 10% on an article marked at Rs 2,500. Find the effective discount percentage and the final selling price.

  2. 2. Find the simple interest on Rs 8,000 at 9% per annum for 3 years and 4 months.

  3. 3. A sum of Rs 15,000 is invested at compound interest, compounded annually, at 10% per annum. Find the compound interest earned after 2 years.

  4. 4. The difference between the compound interest and simple interest on a certain sum for 2 years at 8% per annum is Rs 512. Find the sum.

  5. 5. A can complete a piece of work in 15 days and B can complete the same work in 10 days. They work together for 3 days, after which A leaves. In how many more days will B alone finish the remaining work?

  6. 6. Pipe A can fill a tank in 12 hours and Pipe B can fill it in 18 hours, while Pipe C can empty the full tank in 9 hours. If all three pipes are opened together, in how many hours will the tank be filled?

  7. 7. A car travels 60 km at a speed of 40 km/h and the next 90 km at a speed of 60 km/h. Find its average speed for the entire journey.

  8. 8. A train 240 metres long is running at a speed of 63 km/h. Find the time it takes to cross a platform 360 metres long.

  9. 9. In what ratio must a shopkeeper mix tea worth Rs 180 per kg with tea worth Rs 280 per kg so that, on selling the mixture at Rs 264 per kg, he earns a profit of 20%?

  10. 10. A container has 40 litres of a mixture of milk and water in the ratio 3:1. How many litres of water must be added to the mixture so that the resulting ratio of milk to water becomes 3:2?

Time-traps & syllabus quirks

  • Data Interpretation sub-questions usually reuse totals from the same table read. Re-scanning the table for every sub-question instead of reading it once wastes minutes that don't come back.
  • Approximation questions are designed to be solved with rounded numbers; working out an exact answer costs time for no extra marks, since the options are always spread far enough apart.
  • With a -0.25 penalty per wrong answer, a rushed guess on a lengthy DI or quadratic-comparison question costs more than skipping it and returning only if time remains.

Frequently asked questions

How many questions does IBPS PO Quantitative Aptitude have in Prelims?

35 questions worth 30 marks in the revised pattern, with +1 for each correct answer and -0.25 for each wrong answer, inside a 20-minute sectional window.

What's a realistic target score for IBPS PO Quant Prelims?

19-22 out of 30 is a strong target, since Data Interpretation and quadratic-comparison questions take longer per mark than Reasoning or English.

Is IBPS PO Quant tested again in Mains?

Yes, as Data Analysis & Interpretation, a heavier 40-question, 60-mark module in 45 minutes that leans further into table and graph reading and less into short arithmetic.

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